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লেখকের নাম    : তামিম শাহরিয়ার সুবিন

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বইয়ের নাম     : C & C++ Programming

লেখকের নাম    : Tanbir Ahmed Razib

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UVA SOLUTION

LIST OF UVA PROBLEM SOLUTION

Problem No    Problem Name          Solution Link      Download

UVA10018                   Reverse and Add                           SOLUTION                     DOWNLOAD

UVA10346                   Peter's Smokes                            SOLUTION                     DOWNLOAD
UVA11854                   Egypt                                               SOLUTION                     DOWNLOAD

LIGHTOJ1000 - Greetings from LightOJ

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1000 - Greetings from LightOJ

Problem Link:

Solution:

#include < iostream >

using namespace std;

int main(){

    int a,b,sum,t,cases=0;

    cin>>t;

    while(t--){

        cin>>a>>b;

        cout<< "Case " << ++cases << ": " << a+b << endl;

    }

}

Problem & Solution Download

LIGHTOJ1294 - Positive Negative Sign

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1294 - Positive Negative Sign

Problem Link:

Solution:

#include < stdio.h >

int main(){
    int t, cases=0;
    long long int a, n, m;
    scanf("%d",&t);
    while(t--){
        scanf("%lld %lld", &n, &m);
        n = n/2;
        m = m*n;
        printf("Case %d: %lld\n",++cases,m);
    }
    return 0;
}

Problem & Solution Download

UVA10346 - Peter's Smokes

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10346 - Peter's Smokes

Problem Link:

Solution:

#include < stdio.h >

int main()
{
    int n,k,b,a;
    while(scanf("%d %d",&n,&k)==2)
    {
        b=n;
        while(n>=k)
        {
            b=b+n/k;
            n=(n/k)+(n%k);
        }
        printf("%d\n",b);
    }
}


Problem & Solution Download

UVA12502 - Three Families

12502 - Three Families

Problem Link:

Solution:

#include < stdio.h >

int main(){
    int t,a,b,c;
    int Totalworkhours, Totalworkminute, eachworkminute, extraminute, Aget;
    scanf("%d",&t);
    while(t--){
        scanf("%d %d %d",&a,&b,&c);
        Totalworkhours = a+b;
        Totalworkminute = Totalworkhours * 60;
        eachworkminute = Totalworkminute/3;
        extraminute = a * 60 - eachworkminute;
        Aget = (c * extraminute)/eachworkminute;

        if(Aget<=0)
            printf("0\n");
        else
            printf("%d\n",Aget);
    }
}

UVA10018 - Reverse and Add

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10018 - Reverse and Add

Problem Link:

Solution:

#include < stdio.h >

int main()
{
    long long int t,n,d,c,r,sum;
    scanf("%lld",&t);
    while(t--)
    {
        scanf("%lld",&n);
        d=n;
        c=0;
        while(1)
        {
            sum=0;
            while(d>0)
            {
                r=d%10;
                sum=sum*10+r;
                d=d/10;
            }
            if(n==sum)
            break;
            else
            {
                d=sum+n;
                n=sum+n;
                c++;
            }
        }
        printf("%lld %lld\n",c,sum);
    }
}

Problem & Solution Download

UVA11854 - Egypt

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11854 - Egypt

Problem Link:

Solution:

#include < stdio.h >

int main()
{
    int a,b,c;
    while(scanf("%d %d %d",&a,&b,&c)==3)
    {
    if(a==0&&b==0&&c==0)
    break;
    if(a<=0||b<=0||c<=0)
    printf("wrong\n");
    else if(a*a==b*b+c*c)
    printf("right\n");
    else if(b*b==a*a+c*c)
    printf("right\n");
    else if(c*c==b*b+a*a)
    printf("right\n");
    else
    printf("wrong\n");
    }
}

Problem & Solution Download

UVA11172 - Relational Operator

11172 - Relational Operator

Problem Link:

Solution:

#include < stdio.h >

int main(){
    int t, a,b;
    scanf("%d",&t);
    while(t--){
        scanf("%d %d",&a,&b);
        if(a < b)
            printf("<");
        else if(a > b)
            printf(">");
        else if(a == b)
            printf("=");
            printf("\n");
    }
}

ACM HDU Problem Solution 1089-A+B for Input-Output Practice (I)

Problem 1089

A+B for Input-Output Practice (I)

Problem Link:

Solution:

#include < stdio.h >

int main(){
    int a,b;
    while(scanf("%d %d",&a,&b)==2){
        printf("%d\n",a+b);
    }
    return 0;
}

ACM HDU Problem Solution 1001 - Sum Problem

Problem 1001 - Sum Problem

Problem Link

Solution:

#include

int main(){
    int n,sum,p;
    while(scanf("%d",&n)==1){
            sum=0;
            for(p=1;p<=n;p++)
                sum = sum + p;
                printf("%d\n\n",sum);
    }
    return 0;
}

ACM HDU Problem Solution 1000 - A + B Problem

Problem 1000 - A + B Problem

#include<stdio.h>

int main(){
    int a,b;
    while(scanf("%d %d",&a,&b)==2){
    printf("%d\n",a+b);
    }
    return 0;
}